Any algebra experts here? Need help with an equation please

rodeojones903

rodeojones903

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So I'm working on the review for a finance class on valuation of mergers and acquisitions and I hit a snag. On the last part of a huge problem I have worked it down to this equation for finding the number of new shares to issue, but for the life of me can't remember how to do it (I know I should know it but I've gone blank).

[50,891,500/(1,500,000 + y)] * y = 10,500,000

I need to solve for y, but for the life of me can't remember how to do it with two variables that are the same and I have not done it in what feels like years. Anyone care to help? :D

I don't need just the answer though, but the final equation used to find the answer. (which in my check figures is 372,245 so I hope I'm setting it up right).
 
[quote name='rodeojones903']So I working on the review for a finance class on valuation of mergers and acquisitions and I hit a snag. On the last part of a huge problem I have worked it down to this equation for finding the number of new shares to issue, but for the life of me can't remember how to do it (I know I should know it but I've gone blank).

[50,891,500/(1,500,000 + y)] * y = 10,500,000

I need to solve for y, but for the life of me can't remember how to do it with two variables that are the same and I have not done it in what feels like years. Anyone care to help? :D[/QUOTE]

The quickest way to do this would be graphically, if you've got a calculator that can handle it.

If that won't work, multiply both sides of the equation by the denominator of your fraction, and you should be able to solve that for y.

50,891,500*y = 10,500,000 * (1,500,000 + y)
 
Can't help you specifically but two stabs in the dark for ya.

First, factoring.

Second, isolate a y so that you have y= something and plug that into the other y.

Probably completely wrong, but maybe it'll spark your memory.
 
Got it.

[50,891,500/(1,500,000 + y)] * y = 10,500,000

50,891,500y / (1,500,000 + y) = 10,500,000

[(50,891,500y/(1,500,000+y)] * (1,500,000+y) = 10,500,000 * (1,500,000 + y)

50,891,500y = 15,750,000,000,000 + 10,500,000y

50,891,500y - 10,500,000y = 15,750,000,000,000 + 10,500,000y - 10,500,000y

40,391,500y = 15,750,000,000,000

y = 389933.52561
 
[quote name='Gothic Walrus']

If that won't work, multiply both sides of the equation by the denominator of your fraction, and you should be able to solve that for y.

50,891,500*y = 10,500,000 * (1,500,000 + y)[/quote]

yea this will work, you are going to have a real ugly number
 
I'm a little confused by your brackets.

[50,891,500/(1,500,000 + y)] * y = 10,500,000

Is the left side of the equation supposed to look like this:

50,891,500 (*y)
1,500,000 + y

where the y can just be included with the top, or:

50,891,500
(1,500,000 + y)y

where it is grouped on the bottom?

If it's on the top, then I believe fatherofcaitlyn is correct.
 
Lol, that problem is extremely easy, but then again, I love math and willing to do math problems most any time of the day. ;)

I feel like doing a Fourier Series right now. Just be glad you never had to do one.
 
[quote name='mikej012']I'm a little confused by your brackets.

[50,891,500/(1,500,000 + y)] * y = 10,500,000

Is the left side of the equation supposed to look like this:

50,891,500 (*y)
1,500,000 + y

where the y can just be included with the top, or:

50,891,500
(1,500,000 + y)y

where it is grouped on the bottom?

If it's on the top, then I believe fatherofcaitlyn is correct.[/QUOTE]


Everything in the brackets is multiplied by y at the end.
 
[quote name='mikej012']I'm a little confused by your brackets.

[50,891,500/(1,500,000 + y)] * y = 10,500,000

Is the left side of the equation supposed to look like this:

50,891,500 (*y)
1,500,000 + y

where the y can just be included with the top, or:

50,891,500
(1,500,000 + y)y

where it is grouped on the bottom?

If it's on the top, then I believe fatherofcaitlyn is correct.[/QUOTE]


Everything in the brackets is multiplied by y at the end.

50,891,500
1,500,000 + y


all of that with big brackets and then multiplied by y
 
Gotcha. Having it separate like that instead of including it in the top in the first place threw me off. I was working it with the y on the bottom and was thinking, "There's no way this is right. Either his equation is wrong or I read it wrong." So yeah, fatherofcaitlyn is right. But you already knew that.
 
Okay guys! Nows solve mine.

Sin (x) - 2 = 3^(1/2) * Cos (x)

Solve in radians. It's the only one I bombed on the test. Couldn't for the life of me figure it out.
 
Oh, the irony.

picture3ro6.png
 
Usually these threads start and end with:

"Do you own fucking homework."

What gives?

Guess it's a couple days old now though.
 
[quote name='Magehart']Okay guys! Nows solve mine.

Sin (x) - 2 = 3^(1/2) * Cos (x)

Solve in radians. It's the only one I bombed on the test. Couldn't for the life of me figure it out.[/QUOTE]

Mathematica says (5*pi)/6.

I haven't figured out the whole "work" part yet though...that's a really tricky one, and I've always been terrible at these kinds of problems.
 
[quote name='Rig']Usually these threads start and end with:

"Do you own fucking homework."

What gives?

Guess it's a couple days old now though.[/QUOTE]

Yeah, they usually do which is why I felt kinda bad for asking. This final is somewhat strange though. Its for my capstone course Advanced Financial Management, and to throw us for a loop the final has topics/ideas that were not covered in the class to see how we will react to new things thrown our way in the work place. This problem for review was something that we have never done before to start us preparing and thinking outside of the box. If anyone wants I can type up the 3 pages of work I did before that to show I was not trying to get out of doing work, just couldn't remember how to do it since its been a while. :D
 
God, I use to be pretty decent at working out algebraic equations, but my problem was usually when it broke down to simple math. I really should do some sort of stuff online to refresh myself with it.
 
[quote name='rodeojones903']Yeah, they usually do which is why I felt kinda bad for asking. This final is somewhat strange though. Its for my capstone course Advanced Financial Management, and to throw us for a loop the final has topics/ideas that were not covered in the class to see how we will react to new things thrown our way in the work place. This problem for review was something that we have never done before to start us preparing and thinking outside of the box. If anyone wants I can type up the 3 pages of work I did before that to show I was not trying to get out of doing work, just couldn't remember how to do it since its been a while. :D[/quote]

I was just surprised. It could be that you are more respected than the others that make such a thread. I came in expecting to see/read the worst.

Good luck with your work.
 
[quote name='Magehart']Okay guys! Nows solve mine.

Sin (x) - 2 = 3^(1/2) * Cos (x)

Solve in radians. It's the only one I bombed on the test. Couldn't for the life of me figure it out.[/quote]

Divide by cosine:

tan(x) = 3^(1/2)+2

x = 1.31rad (which is 5pi/12) or 75degrees
 
Is this turning into a math question thread, if so I will start asking for some proofs. Prove the Riemann Hypothesis.
 
[quote name='ChibiJosh']Divide by cosine:

tan(x) = 3^(1/2)+2

x = 1.31rad (which is 5pi/12) or 75degrees[/quote]

You can't divide over addition like that, your equation should read:
Code: 
tan(x) = 3^(1/2) + 2/cos(x)
 
[quote name='c0rnpwn']You can't divide over addition like that, your equation should read:
Code: 
tan(x) = 3^(1/2) + 2/cos(x)
[/quote]

That's true. Damn. I just looked at a Trig table and saw sqrt(3)+2 for tan and just assumed.
 
I got it!

divide by cos: tanx = sqrt(3) + 2/cosx
square both sides: tan^2x = 3 + 4/cos^2(x)
use power reduction formula: [1-cos2x/1+cos2x] = 3 + 8/(1+cos2x)
multiply by 1+cos2x: 1-cos2x = 3(1+cos2x) + 8
collect terms: cos2x = 10/4

x= cos^-1(10/4)/2

Right, now back to studying for my linear algebra final.
 
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