Hey Cags, i need some math help

Dude, just post your problems and I'm sure some math-geek like myself will be happy to help you. Also give us a little more info about what type of math we're taking about here... Algebra? Trig? Calculus?
 
[quote name='Professor Oreo']Dude, just post your problems and I'm sure some math-geek like myself will be happy to help you. Also give us a little more info about what type of math we're taking about here... Algebra? Trig? Calculus?[/QUOTE]

Probably something as difficult as 2 + 2.
 
just for fun... post it. I'm sure we could all do with a little brain food.

Unless it's something annoying and repetitive.

Of course, morality aside, perhaps you should question the wisdom of not doing it yourself... but I'm never one to judge.

Edit: OMG, another San Diegan.
 
post it, I suck at math but love watching math geeks in action. Man do they get into that shit, ti-8900 calculators a blazin' and what not.

Go! math geeks! Go!
 
[quote name='rockhero']I guarantee you I can do it, just post it here.[/QUOTE]

Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)
 
[quote name='eldad9']Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)[/QUOTE]
The smart thing to do here would be to use logarithms. I think.

I always did hate that concept.
 
[quote name='eldad9']Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)[/QUOTE]

Easy if you're Andrew Wiles. Actually, it was pretty rough on him too...
 
[quote name='eldad9']Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)[/QUOTE]


Oh okay, this ones easy. say x = 3, y = -2 and z = 0. if you take the 3 and muliply it by the ABSOLUTE VALUE of -2, that is to say, 2, then you will have 6. after you get this 6, look it at carefully. if it doesn't respond with a glimmer of hope, then go jump off a bridge, because life is not worth living. If you get a remainder, go back and check the absolute value, which should be somewhere on the ummmmm number line. if it's not on the number line, then I think that means your sexual preferences are in fluctuation and that you must foil out two to the third, according to the side angle side theorem. If you don't successfully foil, then try picking up a random chick at the bar and giving her a pink sock. Take a pic, post it in this thread to prove your answer.

Hope that helps ;-)
 
[quote name='opportunity777']If it's something like Real Analysis you are shit out of luck :lol:[/QUOTE]

I have some Real Analysis knowledge. Just post your problem, and we'll do what we can.
 
[quote name='eldad9']Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)[/QUOTE]

Ok, Fermat.
 
I wanna see if I can do it. I haven't had math in years. The last time I took it was 11th grade. Oddest thing was I remember my sat math grade went from under 500 in 11th to over 600 in 12th grade even though I hadn't done anything more than mental math in almost a year. It's been a while since, so maybe I'm a math genius now?
 
[quote name='eldad9']I don't think any of us can do it except rockhero.

Oh, and bonus points if he can prove it in under 100 pages.[/QUOTE]

Hahah I'm not willing to disown my family and live in an attic for years with a total bizarre and unhealthy obsession over proving that problem.
 
[quote name='eldad9']Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)[/QUOTE]



easy. Stand up in middle of class, scream as loud as you can and run out the door swinging your arms as fast as you can.


belive it or not we did have someone do this one time , (well they wasnt swinging their arms but they stood up and took off running screaming out of the room) never seen them again in that class, must of dropped.... It was funny as hell
 
[quote name='eldad9']Prove or disprove: there are no positive integers x, y, and z such that x**n + y**n = z**n where n is a natural number greater than 2.

(** stands for power, that is, 2**3 = two to the third = 8)[/QUOTE]


English only please :lol:

I barely passed algebra.
 
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