Im stuck on a math problem! (simple algebra but i can't solve it!)
- Thread starter samisdumm
- Start date
Canadian_Man
CAGiversary!
Assuming you're still at the stage where all the solutions are clean answers, are you sure about the coefficients?
You'd have expand your trinomial into a multiplication (the bracket x bracket format) and because f(a) is squared, that would lead me to believe both sets of brackets should have the same values inside, so that it just become bracket^2 and the square root being your solution, f(a).
You'd have expand your trinomial into a multiplication (the bracket x bracket format) and because f(a) is squared, that would lead me to believe both sets of brackets should have the same values inside, so that it just become bracket^2 and the square root being your solution, f(a).
Canadian_Man
CAGiversary!
1) Expand the trinomial.
2) The square root of your expanded trinomial will be equal to f(a)
2) The square root of your expanded trinomial will be equal to f(a)
[quote name='samisdumm']2x^2 - x + 4
and we're solving for [f(a)]^2
maybe that would make it more clear?
i know if its f(a) its 2a^2-a+4
[/QUOTE]
to be clear, your question is something like: "Given f(x) = 2x^2 - x + 4, find [f(a)]^2" ?
If so, first plug a in where every x is to get f(a), which is: 2a^2 - a + 4
Now, since you're looking for [f(a)]^2, square f(a) found from the above line: (2a^2 - a + 4) * (2a^2 - a + 4)
and we're solving for [f(a)]^2
maybe that would make it more clear?
i know if its f(a) its 2a^2-a+4
[/QUOTE]
to be clear, your question is something like: "Given f(x) = 2x^2 - x + 4, find [f(a)]^2" ?
If so, first plug a in where every x is to get f(a), which is: 2a^2 - a + 4
Now, since you're looking for [f(a)]^2, square f(a) found from the above line: (2a^2 - a + 4) * (2a^2 - a + 4)
bread's done